4cos^4x-5sin^2x-4=0

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Solution for 4cos^4x-5sin^2x-4=0 equation: 


Simplifying
4cos4x + -5sin2x + -4 = 0

Reorder the terms:
-4 + 4cos4x + -5in2sx = 0

Solving
-4 + 4cos4x + -5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4cos4x + 4 + -5in2sx = 0 + 4

Reorder the terms:
-4 + 4 + 4cos4x + -5in2sx = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4cos4x + -5in2sx = 0 + 4
4cos4x + -5in2sx = 0 + 4

Combine like terms: 0 + 4 = 4
4cos4x + -5in2sx = 4

Add '5in2sx' to each side of the equation.
4cos4x + -5in2sx + 5in2sx = 4 + 5in2sx

Combine like terms: -5in2sx + 5in2sx = 0
4cos4x + 0 = 4 + 5in2sx
4cos4x = 4 + 5in2sx

Divide each side by '4os4x'.
c = o-1s-4x-1 + 1.25in2o-1s-3

Simplifying
c = o-1s-4x-1 + 1.25in2o-1s-3

Reorder the terms:
c = 1.25in2o-1s-3 + o-1s-4x-1

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